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CLASS 12 · MATHEMATICS · CHAPTER 4

Minors, Cofactors
& Adjoint

The building blocks for finding inverse matrices and expanding determinants.

1

Minor of an Element

📘 Definition — Minor (Mᵢⱼ)

The minor of element aᵢⱼ is the determinant of the sub-matrix obtained by deleting the i-th row and j-th column from the matrix.

For a 3×3 matrix A with element at position (i, j), we delete that row and column, and the determinant of the remaining 2×2 matrix is Mᵢⱼ.

🔍

The minor is always a determinant (a number), not a matrix. For a 3×3 matrix, each minor is a 2×2 determinant.

✏️ Visual Example
Find M₁₁ for A = [[1,2,3],[4,5,6],[7,8,9]]
ORIGINAL MATRIX
123
456
789
SUBMATRIX (delete R₁, C₁)
56
89

M₁₁ = |5,6;8,9| = 45 − 48 = −3

✏️ More Minors
Find M₁₂ and M₂₁
M₁₂

Delete R₁ and C₂: submatrix [[4,6],[7,9]] → |4,6;7,9| = 36−42 = −6

M₂₁

Delete R₂ and C₁: submatrix [[2,3],[8,9]] → |2,3;8,9| = 18−24 = −6

2

Cofactor of an Element

📘 Definition — Cofactor (Aᵢⱼ or Cᵢⱼ)

The cofactor of element aᵢⱼ is the minor with an appropriate sign determined by position:

Aᵢⱼ = (−1)^(i+j) × Mᵢⱼ

The sign depends on whether (i + j) is even (+) or odd (−). This creates the checkerboard sign pattern:

+
+
+
+
+

Sign pattern for 3×3 (−1)^(i+j)

Cofactor Formula
Aᵢⱼ = (−1)^(i+j) · Mᵢⱼ
✏️ Solved Example
Find cofactors A₁₁, A₁₂, A₁₃ for A = [[1,2,3],[4,5,6],[7,8,9]]
A₁₁

(−1)^(1+1) × M₁₁ = (+1)(−3) = −3

A₁₂

(−1)^(1+2) × M₁₂ = (−1)(−6) = +6

A₁₃

M₁₃ = |4,5;7,8| = 32−35 = −3; (−1)^(1+3)(−3) = (+1)(−3) = −3

Determinant Expansion via Cofactors: |A| = a₁₁A₁₁ + a₁₂A₁₂ + a₁₃A₁₃ = sum of (element × its cofactor) along any row or column.

3

Adjoint (Adjugate) of a Matrix

📘 Definition — adj(A)

The adjoint (or adjugate) of a matrix A is the transpose of the cofactor matrix.

adj(A) = [Aᵢⱼ]ᵀ

Where Aᵢⱼ is the cofactor of element aᵢⱼ. Each element of adj(A) at position (i,j) is the cofactor Aⱼᵢ (note the swap!).

Step-by-step to find adj(A):

1

Find ALL 9 cofactors (for a 3×3 matrix)

2

Write them as the cofactor matrix C

3

Transpose C → this gives adj(A)

✏️ Complete Example
Find adj(A) for A = [[2,1,3],[1,0,1],[−1,2,1]]
C₁₁

(−1)²|0,1;2,1| = (0−2) = −2

C₁₂

(−1)³|1,1;−1,1| = −(1+1) = −2

C₁₃

(−1)⁴|1,0;−1,2| = (2−0) = 2

C₂₁

(−1)³|1,3;2,1| = −(1−6) = 5

C₂₂

(−1)⁴|2,3;−1,1| = (2+3) = 5

C₂₃

(−1)⁵|2,1;−1,2| = −(4+1) = −5

C₃₁

(−1)⁴|1,3;0,1| = (1−0) = 1

C₃₂

(−1)⁵|2,3;1,1| = −(2−3) = 1

C₃₃

(−1)⁶|2,1;1,0| = (0−1) = −1

adj(A) = Transpose of cofactor matrix:
adj(A) = [[−2, 5, 1],[−2, 5, 1],[2, −5, −1]]

4

Key Result: A · adj(A) = |A| · I

⭐ Fundamental Result

A · adj(A) = adj(A) · A = |A| · I

Where I is the identity matrix. This forms the foundation for finding the inverse of a matrix.

This result tells us:

TermMeaningHow to Get It
MᵢⱼMinor of aᵢⱼDelete row i & col j → determinant
Aᵢⱼ or CᵢⱼCofactor of aᵢⱼ(−1)^(i+j) × Mᵢⱼ
adj(A)Adjoint / AdjugateTranspose of cofactor matrix