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CLASS 12 · MATHEMATICS · CHAPTER 5

Exponential &
Logarithmic Functions

Derivatives of eˣ, aˣ, ln x, and logₐx — and the powerful properties behind them.

1

Exponential Function — eˣ

The natural exponential function eˣ is the most important function in calculus. Its unique property is that it is its own derivative.

⭐ Most Important Derivative
d/dx (eˣ) = eˣ

More generally, using the chain rule:

General Exponential
d/dx [e^f(x)] = e^f(x) · f'(x)
Chain rule applied to eˣ
Base-a Exponential
d/dx [aˣ] = aˣ · ln a
a > 0, a ≠ 1
✏️ Examples
Find derivatives of the following
a

d/dx[e^(3x)] = e^(3x) · 3 = 3e^(3x)

b

d/dx[e^(x²)] = e^(x²) · 2x = 2x·e^(x²)

c

d/dx[e^(sin x)] = e^(sin x) · cos x = cos x · e^(sin x)

d

d/dx[2ˣ] = 2ˣ · ln 2 = 2ˣ ln 2

2

Logarithmic Function — ln x

The natural logarithm ln x (log base e) has a beautifully simple derivative:

Natural Log Derivative
d/dx (ln x) = 1/x    (x > 0)

d/dx [ln f(x)] = f'(x) / f(x)    (chain rule)
Log base a
d/dx [logₐx] = 1 / (x · ln a)
Convert using logₐx = ln x / ln a
Log of composite
d/dx [log(f(x))] = f'(x) / (f(x)·ln a)
Chain rule applied
✏️ Examples
Find derivatives
a

d/dx[ln(x²+1)] = 2x/(x²+1) = 2x/(x²+1)

b

d/dx[ln(sin x)] = cos x / sin x = cot x

c

d/dx[log₁₀(x)] = 1/(x · ln 10) = 1/(x ln 10)

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Properties of Logarithms (For Differentiation)

These log properties simplify complex expressions before differentiation:

Product Rule
ln(ab) = ln a + ln b
Quotient Rule
ln(a/b) = ln a − ln b
Power Rule
ln(aⁿ) = n · ln a
Base Change
logₐb = ln b / ln a
Identity
e^(ln x) = x
Inverse
ln(eˣ) = x

💡 Tip: Before differentiating complex products/quotients/powers — take the natural log first to simplify (logarithmic differentiation, see topic 4).

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Summary — All Exp & Log Derivatives

FunctionDerivativeCondition
all x
e^(f(x))f'(x) · e^f(x)chain rule
aˣ ln aa > 0, a ≠ 1
a^(f(x))a^f(x) · ln a · f'(x)chain rule
ln x1/xx > 0
ln(f(x))f'(x) / f(x)f(x) > 0
logₐx1 / (x ln a)x > 0
✏️ Combined Example
Differentiate y = e^(x²) · ln(3x)
1

Use Product Rule: u = e^(x²), v = ln(3x)

2

u' = 2x·e^(x²)  |  v' = 3/(3x) = 1/x

3

dy/dx = u'v + uv' = 2x·e^(x²)·ln(3x) + e^(x²)·(1/x)

= e^(x²) [2x·ln(3x) + 1/x]